2. Solve the following matrix equation for a, b, c, and d.

a−3d = 2 and a−2d = 3. Therefore, a = 5, b = −3, c = 4, and d = 1
3.

(e) Impossible

(i) tr(D) = 5
(j) tr(D − 3E) = −25
(k) 4tr(7B)=168
(l) undefined
5.



13.

1.4. Inverses; Rules of Matrix Arithmetic
4.


7. In each part, use the given information to find A.


14. Show that if a square matrix A satisfies A2 − 3A + I = 0, then

As we do not know the existence of A−1, we can not use A−1 like

As A2 − 3A + I = 0, I = 3A − A2 =
A(3I − A) and I = 3A − A2 =
(3I − A)A
Therefore, A−1 = 3I − A